Does anyone know any quotes from 1984 about war is peace?

# Does anyone know any quotes from 1984 about war is peace?

• MATH

∫3√13√(81+x2)dx∫133(81+x2)dx Evaluate the integral.

You need to evaluate the definite integral using the fundamental theorem of calculus, such that: ∫baf(x)dx=F(b)−F(a)∫abf(x)dx=F(b)-F(a)

• MATH

∫10(cosh(t))dt∫01(cosh(t))dt Evaluate the integral.

We have to evaluate the integral ∫10cosh(t)dt∫01cosh(t)dt  We know that the integral of cosh(t) = sinh(t) . Therefore we can write, ∫10cosh(t)dt=[sinh(t)]10∫01cosh(t)dt=[sinh(t)]01…

• MATH

∫10(xe+ex)dx∫01(xe+ex)dx Evaluate the integral.

∫10(xe+ex)dx∫01(xe+ex)dx To evaluate this, apply the formulas ∫undu=un+1n+1∫undu=un+1n+1 and ∫eudu=eu∫eudu=eu . =(xe+1e+1+ex)∣∣∣10=(xe+1e+1+ex)∣01 Then, plug-in the limits of integral as follows…

• MATH

∫181(3z−−√)dz∫118(3z)dz Evaluate the integral.

Evaluate ∫181(3z)12dz∫118(3z)12dz =∫1813–√z−12dz=∫1183z-12dz =3–√∫181z−12dz=3∫118z-12dzIntegrate the function. =3–√[z1212]=3–√[2z12]=3[z1212]=3[2z12] Evaluate the function from 1 to 18….

• MATH

∫21(v3+3v6v4)dv∫12(v3+3v6v4)dv Evaluate the integral.

∫21(v3+3v6v4)dv∫12(v3+3v6v4)dv simplify the integrand and apply the sum rule, =∫21(v3v4+3v6v4)dv=∫12(v3v4+3v6v4)dv =∫21(1v+3v2)dv=∫12(1v+3v2)dv using the following common integrals ∫1xdx=ln(x)∫1xdx=ln(x) and…

• MATH

∫30(2sin(x)−ex)dx∫03(2sin(x)-ex)dx Evaluate the integral.

You need to evaluate the definite integral using the fundamental theorem of calculus, such that: ∫baf(u)du=F(b)−F(a)∫abf(u)du=F(b)-F(a) ∫30(2sinx−ex)dx=∫302sinxdx−∫30exdx∫03(2sinx-ex)dx=∫032sinxdx-∫03exdx…

• MATH

∫21(1+2y)2dy∫12(1+2y)2dy Evaluate the integral.

∫21(1+2y)2dy∫12(1+2y)2dy =∫21((1)2+2⋅2y⋅1+(2y)2)dy=∫12((1)2+2⋅2y⋅1+(2y)2)dy =∫21(1+4y+4y2)dy=∫12(1+4y+4y2)dy =[y+4y22+4y33]21=[y+4y22+4y33]12 =[y+2y2+4y33]21=[y+2y2+4y33]12 =[2+2(2)2+4(23)3]−[1+2(1)2+4(1)33]=[2+2(2)2+4(23)3]-[1+2(1)2+4(1)33]…

• MATH

∫π40(sec(θ)tan(θ))dθ∫0π4(sec(θ)tan(θ))dθ Evaluate the integral.

∫π40(sec(θ)tan(θ))dθ∫0π4(sec(θ)tan(θ))dθ Take note that the derivative of secant is ddθ(sec(θ))=sec(θ)tan(θ)ddθ(sec(θ))=sec(θ)tan(θ) . So taking the integral of sec(theta) tan(theta)…

• MATH

∫π40(sec2(t))dt∫0π4(sec2(t))dt Evaluate the integral.

∫π40sec2(t)dt∫0π4sec2(t)dt Take note that the derivative of tangent is d/(d theta) tan (theta)= sec^2 (theta). So taking the integral of sec^2(t) result to: =tan(t)∣π40=tan(t)∣0π4 Plug-in the…

• MATH

∫20(y−1)(2y+1)dy∫02(y-1)(2y+1)dy Evaluate the integral.

∫20(y−1)(2y+1)dy∫02(y-1)(2y+1)dy Before evaluating, expand the integrand. =∫20(2y2+y−2y−1)dy=∫02(2y2+y-2y-1)dy =∫20(2y2−y−1)dy=∫02(2y2-y-1)dy Then, apply the integral formulas ∫xndx=xn+1n+1∫xndx=xn+1n+1 and ∫cdx=cx∫cdx=cx ….

• MATH

∫91(x−1x−−√)dx∫19(x-1x)dx Evaluate the integral.

Hello! Find the indefinite integral first: ∫(x−1x−−√)dx=∫(x12−x−12)dx=(23)⋅x32−2⋅x12+C.∫(x-1x)dx=∫(x12-x-12)dx=(23)⋅x32-2⋅x12+C.So the definite integral is equal to…

• MATH

∫40(4−t)(t√)dt∫04(4-t)(t)dt Evaluate the integral.

Evaluate ∫40(4−t)(t√)dt∫04(4-t)(t)dt =∫40(4t12−t32)dt=∫04(4t12-t32)dt Integrate the function. ∫an=an+1n+1∫an=an+1n+1 =4t3232−t5252=(83)t32−(25)t52=4t3232-t5252=(83)t32-(25)t52Evaluate the function…

• MATH

∫10(u+2)(u−3)du∫01(u+2)(u-3)du Evaluate the integral.

∫10(u+2)(u−3)du∫01(u+2)(u-3)du =∫10(u2−3u+2u−6)du=∫01(u2-3u+2u-6)du =∫10(u2−u−6)du=∫01(u2-u-6)du =[u33−u22−6u]10=[u33-u22-6u]01 =[133−122−6⋅1]−[033−022−6⋅0]=[133-122-6⋅1]-[033-022-6⋅0] =(13−12−6)=(13-12-6)=2−3−366=2-3-366 =-37/6

• MATH

∫5−5(e)dx∫-55(e)dx Evaluate the integral.

Evaluate ∫5−5(e)dx∫-55(e)dx Please note that e is a constant approximately equal to 2.718. Integrate the function. =ex=ex Evaluate the function from x=-5 to x=5. =e(5)−e(−5)=5e+5e=10e=e(5)-e(-5)=5e+5e=10e =27.183

• MATH

∫ππ6(sin(θ))dθ∫π6π(sin(θ))dθ Evaluate the integral.

You need to evaluate the definite integral using the fundamental theorem of calculus such that ∫baf(x)dx=F(b)−F(a)∫abf(x)dx=F(b)-F(a) ∫ππ6sinθdθ=−cosθ∣∣∣ππ6∫π6πsinθdθ=-cosθ∣π6π…

• MATH

∫81(x−23)dx∫18(x-23)dx Evaluate the integral.

Evaluate ∫81(x−23)dx∫18(x-23)dx Integrate the function. ∫an=an+1n+1∫an=an+1n+1 =x1313=3×13=x1313=3×13 Evaluate the function from x=1 to x=8. =3[813−113]=3[813-113]=3[2−1]=3[2-1] =3

• MATH

∫91(x−−√)dx∫19(x)dx Evaluate the integral.

You need to evaluate the definite integral such that: ∫91x−−√dx=x3232∣∣∣∣91∫19xdx=x3232∣19 ∫91x−−√dx=(23)(99–√−11–√)∫19xdx=(23)(99-11) ∫91x−−√dx=(23)(27−1)∫19xdx=(23)(27-1)

• MATH

∫10(1+(12)u4−(25)u9)du∫01(1+(12)u4-(25)u9)du Evaluate the integral.

∫10(1+(12)u4+(25)u9)du∫01(1+(12)u4+(25)u9)du =[u+(12)(u4+14+1)+(25)(u9+19+1)]10=[u+(12)(u4+14+1)+(25)(u9+19+1)]01 =[u+u510−u1025]10=[1+1510−11025]−[0+0510−01025]=[u+u510-u1025]01=[1+1510-11025]-[0+0510-01025] =(1+110−125)=(1+110-125) =50+5−250=50+5-250 =53/50

• MATH

∫41(5−2t+3t2)dt∫14(5-2t+3t2)dt Evaluate the integral.

∫41(5−2t+3t2)dt∫14(5-2t+3t2)dt apply the sum rule and power rule, =[5t−2t22+3t33]41=[5t-2t22+3t33]14 =[5t−t2+t3]41=[5t-t2+t3]14 =[5⋅4−42+43]−[5⋅1−12+13]=[5⋅4-42+43]-[5⋅1-12+13] =(20−16+64)−(5−1+1)=(20-16+64)-(5-1+1) =(84−16)−(5)=(84-16)-(5) =63

• MATH

∫1−1(x100)dx∫-11(x100)dx Evaluate the integral.

∫1−1x100dx∫-11x100dx To evaluate this, apply the formula ∫xndx=xn+1n+1∫xndx=xn+1n+1 . =x101101∣∣∣1−1=x101101∣-11 Then, plug-in the limits of the integral as follows

• MATH

∫2−1(x3−2x)dx∫-12(x3-2x)dx Evaluate the integral.

You need to evaluate the integral, such that: ∫2−1(x3−2x)dx=∫2−1x3dx−∫2−12xdx∫-12(x3-2x)dx=∫-12x3dx-∫-122xdx ∫2−1(x3−2x)dx=(x44−x2)∣∣∣2−1∫-12(x3-2x)dx=(x44-x2)∣-12

• MATH

y=∫sin(x)1(1+t2−−−−−√)dty=∫1sin(x)(1+t2)dt Use Part 1 of the Fundamental Theorem of Calculus to find…

You need to use the Part 1 of the FTC to evaluate the derivative of the function. You need to notice that the function h(x) = y is the composite of two functions f(x)=∫x11+t2−−−−−√dtf(x)=∫1×1+t2dt and…

• MATH

y=∫11−3x(u31+u2)duy=∫1-3×1(u31+u2)du Use Part 1 of the Fundamental Theorem of Calculus to…

y=∫11−3x(u31+u2)duy=∫1-3×1(u31+u2)du Let t=1-3x dtdx=−3dtdx=-3 dydx=dydt⋅dtdxdydx=dydt⋅dtdx y’=ddx∫11−3x(u31+u2)duy′=ddx∫1-3×1(u31+u2)du =ddt∫1t(u31+u2)du.dtdx=ddt∫t1(u31+u2)du.dtdx =−ddt∫t1(u31+u2)du.dtdx=-ddt∫1t(u31+u2)du.dtdx…

• MATH

y=∫x40(cos2(θ))dθy=∫0x4(cos2(θ))dθ Use Part 1 of the Fundamental Theorem of Calculus to…

Hello! Part 1 of the Fundamental Theorem of Calculus states that for a continuous function ff F’a(x)=f(x),F′a(x)=f(x), where Fa(x)=∫xaf(t)dt.Fa(x)=∫axf(t)dt.Here f(t)=cos2(t)f(t)=cos2(t) and y(x)=F0(x4).y(x)=F0(x4). Therefore…

• MATH

y=∫tan(x)0(t+t√−−−−−−√)dty=∫0tan(x)(t+t)dt Use Part 1 of the Fundamental Theorem of Calculus…

You need to use the Part 1 of the FTC to evaluate the derivative of the function. You need to notice that the function y is the composite of two functions f(x)=∫x11+t√−−−−−−√dtf(x)=∫1×1+tdt and…

• MATH

h(x)=∫x√1(z2z4+1)dzh(x)=∫1x(z2z4+1)dz Use Part 1 of the Fundamental Theorem of Calculus…

Hello! Part 1 of the Fundamental Theorem of Calculus states that for a continuous function ff F’a(x)=f(x),F′a(x)=f(x), where Fa(x)=∫xaf(t)dt.Fa(x)=∫axf(t)dt.Here f(t)=t2t4+1f(t)=t2t4+1 and h(x)=F1(x−−√)h(x)=F1(x)…

• MATH

h(x)=∫ex1(ln(t))dth(x)=∫1ex(ln(t))dt Use Part 1 of the Fundamental Theorem of Calculus to find the…

Hello! Part 1 of the Fundamental Theorem of Calculus states that for a continuous function ff F’a(x)=f(x),F′a(x)=f(x), where Fa(x)=∫xaf(t)dt.Fa(x)=∫axf(t)dt.Here f(t)=ln(t)f(t)=ln(t) and h(x)=F1(ex).h(x)=F1(ex). Therefore…

• MATH

G(x)=∫x1(cos(t√))dtG(x)=∫1x(cos(t))dt Use Part 1 of the Fundamental Theorem of Calculus to find the…

You need to use the Part 1 of the FTC to evaluate the derivative of the function. You need to notice that the function G(x) is the composite of two functions f(x)=∫x1costdtf(x)=∫1xcostdt and

• MATH

F(x)=∫πx(1+sec(t)−−−−−−−−√)dtF(x)=∫xπ(1+sec(t))dt Use Part 1 of the Fundamental Theorem of Calculus to…

F(x)=∫πx1+sec(t)−−−−−−−−√dtF(x)=∫xπ1+sec(t)dt F(x)=−∫xπ1+sec(t)−−−−−−−−√dtF(x)=-∫πx1+sec(t)dt F'(x)=−ddx∫xπ1+sec(t)−−−−−−−−√dtF′(x)=-ddx∫πx1+sec(t)dt F'(x)=−1+sec(x)−−−−−−−−√F′(x)=-1+sec(x)

• MATH

g(r)=∫r0(x2+4−−−−−√)dxg(r)=∫0r(x2+4)dx Use Part 1 of the Fundamental Theorem of Calculus to find…

Hello! Part 1 of the Fundamental Theorem of Calculus states that for a continuous function ff F’a(x)=f(x),F′a(x)=f(x), where Fa(x)=∫xaf(t)dt.Fa(x)=∫axf(t)dt.Here f(t)=t2+4−−−−−√f(t)=t2+4 and g(x)=F0(x).g(x)=F0(x)….

• MATH

g(s)=∫s5(t−t2)8dtg(s)=∫5s(t-t2)8dt Use Part 1 of the Fundamental Theorem of Calculus to find the…

Hello! Part 1 of the Fundamental Theorem of Calculus states that for a continuous function ff F’a(x)=f(x),F′a(x)=f(x), where Fa(x)=∫xaf(t)dt.Fa(x)=∫axf(t)dt.Here f(t)=(t−t2)8f(t)=(t-t2)8 and g(x)=F5(x).g(x)=F5(x). Therefore…

• MATH

g(x)=∫x3(et2−t)dtg(x)=∫3x(et2-t)dt Use Part 1 of the Fundamental Theorem of Calculus to find…

Hello! Part 1 of the Fundamental Theorem of Calculus states that for a continuous function ff F’a(x)=f(x),F′a(x)=f(x), where Fa(x)=∫xaf(t)dt.Fa(x)=∫axf(t)dt.Here f(t)=et2−tf(t)=et2-t and g(x)=F3(x).g(x)=F3(x). Therefore…

• MATH

g(x)=∫x1(1t3+1)dtg(x)=∫1x(1t3+1)dt Use Part 1 of the Fundamental Theorem of Calculus to find…

Hello! Part 1 of the Fundamental Theorem of Calculus states that for a continuous function ff F’a(x)=f(x),F′a(x)=f(x), where Fa(x)=∫xaf(t)dt.Fa(x)=∫axf(t)dt.Here f(t)=1t3+1f(t)=1t3+1 and g(x)=F1(x).g(x)=F1(x). Therefore…

• HISTORY

Why is Thanksgiving celebrated?

There are many different ways to answer this question. Let us look at a few. One way to answer this is to say that Thanksgiving is celebrated as a way of emulating the Pilgrims who were some of…

• SCIENCE

What is the symbiotic relationship between orchids and trees?

A symbiotic relationship is a relationship between two organisms that can be helpful, harmful, or have no effect. A mutualistic relationship benefits both species involved in the relationship….

• THE SCARLET LETTER

Why doesn’t Dimmesdale, in The Scarlet Letter, thrive amidst the people who so admire him?

The Reverend Arthur Dimmesdale, young pastor of the Puritan colony, suffers from crippling guilt over his sin: fathering Hester Prynne’s illegitimate daughter, Pearl. He feels like a fraud in front…

• 1984

What are some dystopian elements in 1984 by George Orwell?

According to Gordon State College, there are a number of elements which define a dystopian novel like 1984. One of these is the portrayal of a “hierarchical society” in which class divisions…

• FAHRENHEIT 451

How does Clarisse define happiness in Fahrenheit 451?

Clarisse defines happiness as caring about things and living life on your own terms. For most of Montag’s society, happiness is defined as succumbing to mass entertainment and other mindless…

• ARISTOTLE

What is the method of teaching of Aristotle

Aristotle was a Greek philosopher. He was mentored by Plato and went on to become the mentor and tutor of Alexander the Great. His philosophical foundations draw upon a variety of sources including…

• POLITICS

Define extremist political organizations.

The problem with defining the term “extremist political organization” is that it is by nature one applied only in the second or third person. In other words, the word “extremism” is one we do not…

• CORIOLANUS

Apart from metaphor, does Shakespeare always assume that marriage is between a husband and wife?

I think it’s safe to conclude that he does assume marriage is between a husband and wife, a man and a woman, at least in the clerical sense. Courtship in Shakespeare’s plays tends to be decently…

• SOCIAL SCIENCES

In philosophy, does the compatibilist position resolve the debate between libertarians and hard…

Compatibilism attempts to resolve the problem of free will and determinism by proposing that the two positions are compatible. Specifically, it asserts that: Determinism is true, that is, all…

• HISTORY

What’s the historical significance of Abraham Lincoln’s Thanksgiving Proclamation?

Lincoln’s Thanksgiving Proclamation, which declared the final day of November a national day of “thanksgiving and praise to Almighty God,” was one of many similar declarations by American…

• HISTORY

What was Christopher Columbus’ motivation to go to the New World?

Columbus’s motivation for his voyage was to reach Asia by sailing west. Neither he nor his backers (nor the people who thought his voyage ill-advised) knew that he would reach the “New World” by…

• MACBETH

Why does Shakespeare use very short lines of dialogue between Macbeth and his wife? What does it…

In Act 2, Scene 2, Macbeth meets Lady Macbeth having just “done the deed” (killed Duncan and his guards). Both Macbeth and Lady Macbeth are very much on edge. Lady Macbeth’s confidence is shaken…

• SCIENCE

What are some pros and cons for space exploration?

Space exploration’s values divide into two categories: human curiosity, and free enterprise (capitalism). The first category holds scientific inquiry — how does the universe work? What are the…

• MISS BRILL

What is the point of view of the story “Miss Brill?

The story “Miss Brill” is narrated from a third person omniscient point of view. This point of view consists on a narrator who detaches emotionally and personally from the story. This way, the…

• HEALTH

In Temkin’s 2003 article for Charity Channel titled “Strategic plans aren’t the answer,”…

To evaluate an article from the perspective of what you and I find confusing or surprising about the content, we usually have to ask ourselves certain questions: 1)Does the author state his/her…

• TO AUTUMN

How does John Keats create vivid images in the poem “To Autumn”?

The poem “To Autumn” employs words that evoke the five senses, including sight, sound, taste, smell, and touch. Keats cleverly and creatively empowers these sense through his use of specific…